4 billion if statements

Just write a script to write more ifs when you need more than 4 billion. Or a just-in-time compiled program triggered by a script that accepts the max value writes the program and then executes it. 😂

Of course, the pseudocode has to be as terrible as possible for the task.

bool even = 0;
print("if(num == 0) { print(\"even\") ;}\r\n")
for(i=1;i<max;i++) {
    if(even) {
        print("elif(num == {0}) { print(\"even\"); }\r\n", num);
        even = 0;
    elif {
        print("elif(num == {0}) { print(\"odd\"); }\r\n", num);
        even = 1;
    }
}

if(even) {
    print("elif(num == {0}) { print(\"even\"); }", max);
    even = 0;
elif {
    print("elif(num == {0}) { print(\"odd\"); }", max);
    even = 1;
}

They certainly are fun. Another favorite of mine (though a bit more practical) is a guy who fixed the Atari ET game http://www.neocomputer.org/projects/et/

I think there are better ways.

1. Even numbers are those which are evenly divisible by 2.
2. Odd numbers are those which are not even.

Therefore,

1. Start at 0
2. Add 2
3. Check, is this your number?
4. Goto 2

When you find your number, you will know it is Even.

I know way you're thinking. And you're right, this is only covering half of the numbers. So I've also worked on a fix. It will run about half as fast, but O() time is technically the same. So yay!

1. Assign the value of 0 to the variables A and B
2. Add 2 to A
3. Check, is this your number?
4. Subtract 2 from B
5. Check, is this your number?
6. Goto 2